Thursday, 31 March 2011
Core3 Worked solutions
June 2010
https://docs.google.com/viewer?a=v&pid=explorer&chrome=true&srcid=0B2J1T-insOmpNzhkYzc0MGItNDBkOS00MTI3LThhNjYtOTlkM2VmYzhmMzUw&hl=en
Jan 2010
https://docs.google.com/viewer?a=v&pid=explorer&chrome=true&srcid=0B2J1T-insOmpYjRhNWY3NzEtYTM2Ni00YmVmLTgzYjctYWYwMzYyMjZiZmUx&hl=en
June 2009
https://docs.google.com/viewer?a=v&pid=explorer&chrome=true&srcid=0B2J1T-insOmpMWFjYmFhMmEtZjQ0Yy00ZGE2LThjNGYtMDBjMjdhNmMwNGE2&hl=en
Jan 2009
https://docs.google.com/viewer?a=v&pid=explorer&chrome=true&srcid=0B2J1T-insOmpOTkxY2MyYTctYzNmNC00MzZjLTk1OTQtZDBmZTc4MDA3YTk0&hl=en
June 2008
https://docs.google.com/viewer?a=v&pid=explorer&chrome=true&srcid=0B2J1T-insOmpYTUwNzAzZTQtYjBkYi00ODlhLTgzMDEtMWQ3ZmExZDEyMmE1&hl=en
Jan 2008
https://docs.google.com/viewer?a=v&pid=explorer&chrome=true&srcid=0B2J1T-insOmpMDBmODNkYmItNzI5Yi00Njg1LThjODktMDRmZTAxZWZlNGI3&hl=en
June 2007
https://docs.google.com/viewer?a=v&pid=explorer&chrome=true&srcid=0B2J1T-insOmpYzA3OWY5YjEtNWJiZi00NjkzLTk5YjctY2RiYTY5OTcxNzBl&hl=en
Jan 2007
https://docs.google.com/viewer?a=v&pid=explorer&chrome=true&srcid=0B2J1T-insOmpZWRmZDI0ODktNzJjZi00NWYwLWExNmMtNzJkNjNkNDFiYmIz&hl=en
June 2006
https://docs.google.com/viewer?a=v&pid=explorer&chrome=true&srcid=0B2J1T-insOmpNzQ2YTU5YzktZjMxNC00N2ZjLWIzMDctYjI3ZjcyZjIxYzJk&hl=en
https://docs.google.com/viewer?a=v&pid=explorer&chrome=true&srcid=0B2J1T-insOmpNzhkYzc0MGItNDBkOS00MTI3LThhNjYtOTlkM2VmYzhmMzUw&hl=en
Jan 2010
https://docs.google.com/viewer?a=v&pid=explorer&chrome=true&srcid=0B2J1T-insOmpYjRhNWY3NzEtYTM2Ni00YmVmLTgzYjctYWYwMzYyMjZiZmUx&hl=en
June 2009
https://docs.google.com/viewer?a=v&pid=explorer&chrome=true&srcid=0B2J1T-insOmpMWFjYmFhMmEtZjQ0Yy00ZGE2LThjNGYtMDBjMjdhNmMwNGE2&hl=en
Jan 2009
https://docs.google.com/viewer?a=v&pid=explorer&chrome=true&srcid=0B2J1T-insOmpOTkxY2MyYTctYzNmNC00MzZjLTk1OTQtZDBmZTc4MDA3YTk0&hl=en
June 2008
https://docs.google.com/viewer?a=v&pid=explorer&chrome=true&srcid=0B2J1T-insOmpYTUwNzAzZTQtYjBkYi00ODlhLTgzMDEtMWQ3ZmExZDEyMmE1&hl=en
Jan 2008
https://docs.google.com/viewer?a=v&pid=explorer&chrome=true&srcid=0B2J1T-insOmpMDBmODNkYmItNzI5Yi00Njg1LThjODktMDRmZTAxZWZlNGI3&hl=en
June 2007
https://docs.google.com/viewer?a=v&pid=explorer&chrome=true&srcid=0B2J1T-insOmpYzA3OWY5YjEtNWJiZi00NjkzLTk5YjctY2RiYTY5OTcxNzBl&hl=en
Jan 2007
https://docs.google.com/viewer?a=v&pid=explorer&chrome=true&srcid=0B2J1T-insOmpZWRmZDI0ODktNzJjZi00NWYwLWExNmMtNzJkNjNkNDFiYmIz&hl=en
June 2006
https://docs.google.com/viewer?a=v&pid=explorer&chrome=true&srcid=0B2J1T-insOmpNzQ2YTU5YzktZjMxNC00N2ZjLWIzMDctYjI3ZjcyZjIxYzJk&hl=en
Wednesday, 30 March 2011
Core4 Rates of change 28/03/11
- Going through homework question about implicit differentiation
- Introducing connected rates of change
- Problems involving rates of change
- Past exam questions involving rates of change
Flipchart:
Past exam questions worksheet:
https://docs.google.com/leaf?id=0B2J1T-insOmpZTk2M2EwNjAtZTY4OS00NDgxLWIxNmMtOTE3NmM5MjFkOTk4&hl=en
Wednesday, 23 March 2011
Core4 Implicit differentiation 23/03/11
- Intro to implicit differentiation
- Using chain rule to differentiate terms in y with respect to x
- Including use of product rule for terms in both x and y
- Using to solve problem involing tangents and normals to curve defined implicitly
- HOMEWORK SET on problem involving stationary points on a curve defined implicitly
Wednesday, 9 March 2011
Monday, 7 March 2011
Core3 a cos + b sin 07/03/11
- Recalling sin and cos addition formulae
- Using form a sin theta + b cos theta = R cos (theta - alpha) etc.
Thursday, 3 March 2011
Thursday 3rd March 2011, Period 5
Just did more differentiation practice.
Differentiate:
y = sec x
y = cosec x
y = cot x
using either Quotient Rule or Chain Rule.
HOMEWORK
Exercise 5F
Q8 (all parts)
due Wednesday 9th March 2011
Differentiate:
y = sec x
y = cosec x
y = cot x
using either Quotient Rule or Chain Rule.
HOMEWORK
Exercise 5F
Q8 (all parts)
due Wednesday 9th March 2011
Wednesday, 2 March 2011
Core4 Using parametric equations 02/03/11
- Reminder of differentiating parametric equations
- Finding gradient at given point of curve defined by parametric equations
- Finding equations of tangent to curve at given point
Subscribe to:
Posts (Atom)